b^2+4b-96=

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Solution for b^2+4b-96= equation:


Simplifying
b2 + 4b + -96 = 0

Reorder the terms:
-96 + 4b + b2 = 0

Solving
-96 + 4b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-12 + -1b)(8 + -1b) = 0

Subproblem 1

Set the factor '(-12 + -1b)' equal to zero and attempt to solve: Simplifying -12 + -1b = 0 Solving -12 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1b = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1b = 0 + 12 -1b = 0 + 12 Combine like terms: 0 + 12 = 12 -1b = 12 Divide each side by '-1'. b = -12 Simplifying b = -12

Subproblem 2

Set the factor '(8 + -1b)' equal to zero and attempt to solve: Simplifying 8 + -1b = 0 Solving 8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1b = 0 + -8 -1b = 0 + -8 Combine like terms: 0 + -8 = -8 -1b = -8 Divide each side by '-1'. b = 8 Simplifying b = 8

Solution

b = {-12, 8}

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